**Puzzle Details:**

Question: In a one-day international cricket match, considering no extras(no wides, no ‘no’ balls, etc.) and no overthrows. What is the maximum number of runs that a batsman can score in an ideal case?

Note:” Here we assume an ideal and little practical scenario. We assume that batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as the opposite team does not catch the ball.”

**The total number of overs in a one-day international cricket match is 50 overs and on each over bowler bowls 6 balls.**

For an ideal case, the batsman will hit a six on each ball. But if he hits six on the last ball of the over, the strike will change in the next over.

which means, In an ideal case, the batsman will hit a six on every ball. But as we know about the rules in cricket, if he hits six on the last ball of the over, the strike will change in the next over and it will go to his partner. Thus, the best he can do in the last ball is make 3 runs so that he retains his striking position even in the next over.

Thus the total runs that he can score in each over: 6 * 5 + 3 = 33 But this will have to go like it only till the 49th over.

From Over 1 to 49:1st ball:- 6 runs(hit six)2nd ball:- 6 runs(hit six)3rd ball:- 6 runs(hit six)4th ball:- 6 runs(hit six)5th ball:- 6 runs(hit six)6th ball:- 3 runs(took 3 runs between the wickets and take back the strike)

= >49*(6*5+3)

In the last over, he can hit a six in the last ball as well as that will be the last ball of the match. Thus runs for the last over will be 6 * 6 = 36. Hence the maximum runs = 33 * 49 + 36 = 1653

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